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Exam Code: 1Z0-047
Exam Name: Oracle (Oracle Database SQL Expert)
One year free update, No help, Full refund!
Total Q&A: 260 Questions and Answers
Last Update: 2014-02-21

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NO.1 View the Exhibit and examine the structure of the EMP table which is not partitioned and not an
index-organized table. Evaluate the following SQL statement: ALTER TABLE emp DROP COLUMN
first_name; Which two statements are true regarding the above command? (Choose two.)
A.The FIRST_NAME column would be dropped provided it does not contain any data.
B.The FIRST_NAME column would be dropped provided at least one or more columns remain in the table.
C.The FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the above
SQL statement.
D.The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the
CASCADE option is used.
Answer:B D

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NO.2 Which two statements are true regarding the execution of the correlated subqueries? (Choose two.)
A.The nested query executes after the outer query returns the row.
B.The nested query executes first and then the outer query executes.
C.The outer query executes only once for the result returned by the inner query.
D.Each row returned by the outer query is evaluated for the results returned by the inner query.
Answer:A D

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NO.3 View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables. You need to create a
view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order. Which
CREATE VIEW statement would create the view successfully?
A.CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date;
C.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;
D.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)||'
NO OF ITEMS' FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date WITH CHECK OPTION;
Answer:B

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NO.4 Evaluate the following CREATE SEQUENCE statement: CREATE SEQUENCE seq1 START WITH 100
INCREMENT BY 10 MAXVALUE 200 CYCLE NOCACHE; The sequence SEQ1 has generated numbers
up to the maximum limit of 200. You issue the following SQL statement: SELECT seq1.nextval FROM
dual; What is displayed by the SELECT statement?
A.1
B.10
C.100
D.an error
Answer:A

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NO.5 View the Exhibit and examine the description of the CUSTOMERS table. You want to add a constraint
on the CUST_FIRST_NAME column of the CUSTOMERS table so that the value inserted in the column
does not have numbers. Which SQL statement would you use to accomplish the task?
A.ALTER TABLE CUSTOMERS ADD CONSTRAINT cust_f_name
CHECK(REGEXP_LIKE(cust_first_name,'